Answer
20.40g
Explanation
Pb(NO3)2(aq) + 2NaBr(aq) ------> PbBr2(s) + 2NaNO3(aq)
stoichiometrically, 1mole of Pb(NO3)2 gives 1mole of PbBr2
molarity = number of moles of solute per liter of solution
moles of Pb(NO3)2 = (0.772mol/1000ml)× 72ml = 0.055584mol
moles of PbBr2 precipitated = 0.055584mol
mass of PbBr2 precipitated = 0.055584mol × 367g/mol = 20.40g
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