Question

Part of a roller coaster ride involves coasting down an incline and entering a loop 6.40 m in diameter. For safety considerations, the roller coaster's speed at the top of the loop must be such that the force of the seat on a rider is equal in magnitude to the rider's weight. From what height above the bottom of the loop must the roller coaster descend to satisfy this requirement?

Answer 1

and the total energy remains constant- PES = mgh (from the start) and Reco Etotal: Pestke Etotal = mgh - Po: 0 (the Pe at the bottom of the loop) and Reg: Etotal Petel - mg (6-4) (the top of the loop) and Retetal = Edetal - Retetal & mgH - mg (85) Mittel: Mg(H-8.5) - © 6.0 at the top of the loop the 'Centrifugal force force of gravity- - Fc = Fo mu²lr = mg V: V R = √3-8 (8.4/2 (R = 624) V = 5.6 m/s Retotal = 1/2mv2 = ½ mgr = 1/2 mg (6) - from ear and @ Retotal & my² mg (H-8.4 = 42 mg 18. Retotal : H-6-01 - 84/4 he H-64 : boyu H = 8m