1)
1)
a)
Oxidation takes place on Anode.
The one with smaller Eo value will be oxidised.
So, the anode reaction is:
Al(s) —> Al3+(aq) + 3 e-
b)
Reduction takes place on Cathode.
The one with greater Eo value will be reduced.
So, the Cathode reaction is:
Co2+(aq) + 2e- —> Co(s)
C)
Overall reaction is:
3 Co2+(aq) + 2Al(s) -> 3 Co(s) + 2Al3+(aq)
d)
Eo cell = Eo cathode - Eo anode
= -0.280 V - (-1.660 V)
= 1.38 V
Answer: 1.38 V
Only 1 question at a time please
A voltaic cell is constructed from a standard Co2+ Co half cell (Eºred = -0.280V) and...
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