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5. Acetic acid (HC,H,Os) is an important component of vinegar. A 10.00-ml sample of vinegar is...
Questions (Pay attention to units and significant figures for the calculations sted molarity of NaOH 1....
Questions (Pay attention to units and significant figures for the calculations sted molarity of NaOH 1. For each of the following circumstances indicate whether the calculated molarity of would be lower, higher or unaffected. Explain your answer in each case a. The inside of the pipet used to transfer the standard HCl solution was wet with water. b. You added 40 mL of water to the titration flask rather than 25 mL. c. The buret, wet with water, was not...
please show all work. thank you A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02), is titrated with 0.5003 M NaOH, and 15.00 mL is required to reach the a....
please show all work. thank you
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02), is titrated with 0.5003 M NaOH, and 15.00 mL is required to reach the a. What is the molarity of the acetic acid? b. If the density of the vinegar is 1.006 g/cm3, what is the mass percent of acetic acid in the vinegar?
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02),...
Acetic acid is an important ingredient of vinegar. A sample of 50.0 mL of a commercial...
Acetic acid is an important ingredient of vinegar. A sample of 50.0 mL of a commercial vinegar is titrated against a 1.00 M NaOH solution. What is the molarity of acetic acid present in the vinegar if 5.75 mL of the base are needed for the titration? Write out the complete balanced molecular equation with phase labels What is the complete ionic equation? (Remember to check if strong/weak) What is the net ionic equation?
Acetic acid is an important ingredient of vinegar. A sample of 50.0 mL of a commercial...
Acetic acid is an important ingredient of vinegar. A sample of 50.0 mL of a commercial vinegar is titrated against a 1.00 M NaOH solution. What is the molarity of acetic acid present in the vinegar if 5.75 mL of the base are needed for the titration? Write out the complete balanced molecular equation with phase labels What is the complete ionic equation? (Remember to check if strong/weak) What is the net ionic equation? Show your work for the calculation...
acetic acid is an important ingredient of vinegar. a sample of 50.0 ml of a commercial...
acetic acid is an important ingredient of vinegar. a sample of 50.0 ml of a commercial vinegar is titrated against a 1.00 M NaOH solution. What is the molarity of acetic acid present in the vinegar if 5.75 ml of the base are needed for the titration?
4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted...
4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...
2. A 25.00 mL sample of acetic acid (CH3COOH) is titrated to the equivalence using 31.08...
2. A 25.00 mL sample of acetic acid (CH3COOH) is titrated to the equivalence using 31.08 mL of 0.1978 M NaOH. What is the balanced neutralization chemical reaction? What is the molarity of the acetic acid in the original sample?
3. The manufacturer of the vinegar used in this experiment claims that the vinegar contains 5% acetic acid by weig...
3. The manufacturer of the vinegar used in this experiment claims that the vinegar contains 5% acetic acid by weight. Using your results, molarity of vinegar, and 1.0 g/ml for a density of vinegar, calculate the % acetic acid by weight. Can you tell if the manufacturer's claims is reasonable? Date Concentration of Acetic Acid in Vinegar: Results Instructor Name Partners Section Data molarity of the NaOH solution, M 0.250 M initial buret reading, ml - 0 ml 32mL Omt...
Acid-Base Titration % A. Concentration of Acetic Acid in Vinegar nei ica's 1. Brand clice Volume...
Acid-Base Titration % A. Concentration of Acetic Acid in Vinegar nei ica's 1. Brand clice Volume 5.0 mL (% on label) 2. Molarity (M) of NaOH Oil M M Trial 1 Trial 2 Trial 3 3. Initial NaOH level in buret 1.8 500 4. Final NaOH level in buret 148.3 5. Volume (mL) of NaOH used 6. Average volume (mL) 7. Average volume in liters (L) mole NaOH 8. Moles of NaOH used in titration (Show calculations.) 9. Moles of...
6.31 M 7. Molarity of acetic acid, HC2H30in vinegar sample (show your calculations) Volume of vinegar...
6.31 M 7. Molarity of acetic acid, HC2H30in vinegar sample (show your calculations) Volume of vinegar sample = 0.003L 0.003L Vinegar contain 0.01893 moles IL 0.01893 = 6.3 IM 0.003 Vinegar contain 8. Grams of Acetic Acid, HC,H,O2 (show your calculations) 1.1368 g HC2H5O2 Grams acid = 12 *MW = 0.01893 mot x 60.052 g/ mot = 1-1368 g 31.90 % L 3 100 9. Percent (m/v) of HC,H,O, in vinegar sample (show your calculations) 3.0 mL vinegar contain 0.01893...
Questions (Pay attention to units and significant figures for the calculations sted molarity of NaOH 1. For each of the following circumstances indicate whether the calculated molarity of would be lower, higher or unaffected. Explain your answer in each case a. The inside of the pipet used to transfer the standard HCl solution was wet with water. b. You added 40 mL of water to the titration flask rather than 25 mL. c. The buret, wet with water, was not...
please show all work. thank you
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02), is titrated with 0.5003 M NaOH, and 15.00 mL is required to reach the a. What is the molarity of the acetic acid? b. If the density of the vinegar is 1.006 g/cm3, what is the mass percent of acetic acid in the vinegar?
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02),...
Acetic acid is an important ingredient of vinegar. A sample of 50.0 mL of a commercial vinegar is titrated against a 1.00 M NaOH solution. What is the molarity of acetic acid present in the vinegar if 5.75 mL of the base are needed for the titration? Write out the complete balanced molecular equation with phase labels What is the complete ionic equation? (Remember to check if strong/weak) What is the net ionic equation?
Acetic acid is an important ingredient of vinegar. A sample of 50.0 mL of a commercial vinegar is titrated against a 1.00 M NaOH solution. What is the molarity of acetic acid present in the vinegar if 5.75 mL of the base are needed for the titration? Write out the complete balanced molecular equation with phase labels What is the complete ionic equation? (Remember to check if strong/weak) What is the net ionic equation? Show your work for the calculation...
4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...
2. A 25.00 mL sample of acetic acid (CH3COOH) is titrated to the equivalence using 31.08 mL of 0.1978 M NaOH. What is the balanced neutralization chemical reaction? What is the molarity of the acetic acid in the original sample?
3. The manufacturer of the vinegar used in this experiment claims that the vinegar contains 5% acetic acid by weight. Using your results, molarity of vinegar, and 1.0 g/ml for a density of vinegar, calculate the % acetic acid by weight. Can you tell if the manufacturer's claims is reasonable? Date Concentration of Acetic Acid in Vinegar: Results Instructor Name Partners Section Data molarity of the NaOH solution, M 0.250 M initial buret reading, ml - 0 ml 32mL Omt...
Acid-Base Titration % A. Concentration of Acetic Acid in Vinegar nei ica's 1. Brand clice Volume 5.0 mL (% on label) 2. Molarity (M) of NaOH Oil M M Trial 1 Trial 2 Trial 3 3. Initial NaOH level in buret 1.8 500 4. Final NaOH level in buret 148.3 5. Volume (mL) of NaOH used 6. Average volume (mL) 7. Average volume in liters (L) mole NaOH 8. Moles of NaOH used in titration (Show calculations.) 9. Moles of...
6.31 M 7. Molarity of acetic acid, HC2H30in vinegar sample (show your calculations) Volume of vinegar sample = 0.003L 0.003L Vinegar contain 0.01893 moles IL 0.01893 = 6.3 IM 0.003 Vinegar contain 8. Grams of Acetic Acid, HC,H,O2 (show your calculations) 1.1368 g HC2H5O2 Grams acid = 12 *MW = 0.01893 mot x 60.052 g/ mot = 1-1368 g 31.90 % L 3 100 9. Percent (m/v) of HC,H,O, in vinegar sample (show your calculations) 3.0 mL vinegar contain 0.01893...
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