2. A 25.00 mL sample of acetic acid (CH3COOH) is titrated to the equivalence using 31.08...
A 25.0 mL sample of 0.150 M acetic acid (CH3COOH) is titrated with 0.150 M NaOH solution. What is the pH at the equivalence point? The Ka of acetic acid is 4.5E-4
A 50.0 ml sample of 0.50 M acetic acid, ch3cooh is titrated with a 0.150 M NaOH solution. calculate the ph after 25.0 ml of the base have been added (ka=1.8x10^-5)
please show all work. thank you
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02), is titrated with 0.5003 M NaOH, and 15.00 mL is required to reach the a. What is the molarity of the acetic acid? b. If the density of the vinegar is 1.006 g/cm3, what is the mass percent of acetic acid in the vinegar?
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02),...
A 20.0 mL sample of a 0.0875 M solution of acetic acid, CH3COOH, is titrated with a 0.115 M solution of KOH. What is the pH after 20.0 mL of KOH solution have been added? For CH3COOH, Ka=1.8 x 10–5.
5. Acetic acid (HC,H,Os) is an important component of vinegar. A 10.00-ml sample of vinegar is titrated with 0.5052 M NaOH, and 16.88 mL are required to neutralize the acetic acid that is present a. Write a balanced equation for this neutralization reaction. b. What is the molarity of the acetic acid in this vinegar? c. If the density of the vinegar is 1.006 g/mL, what is the mass percent of acetic acid in the vinegar? 6. How many milliliters...
a 25.00 ml sample of a weak acid is titrated with 0.225 M NaOH. a total of 12.20 ml of the NaOH is required to reach the equivalence point where the pH is 9.96. determine the value of pka for this weak acid
A weak acid, (HA), has an acid dissociation constant of 4.60∙10–6. A 25.00 ml sample with a concentration of 0.1200 M is titrated with 0.1500 M NaOH. a. Write the equation for the acid dissociation equilibrium. b. What is the pH of the original 0.1200 M sample of HA? c. What is the percent ionization of the 0.1200 M acid? d. Write the equation for the neutralization reaction. e. What is the pH after 8.00 ml NaOH have been added?
14. A weak acid, (HA), has an acid dissociation constant of 2.50 . 10-6. A 25.00 ml sample with a concentration of 0.250 M is titrated with 0.150 M NaOH. a. Write the equation for the acid dissociation equilibrium. b. What is the pH of the original 0.250 M sample of HA? c. What is the percent ionization of the 0.250 M acid? d. Write the equation for the neutralization reaction. e. What is the pH after 12.00 ml 0.150M...
Sulfuric acid (250.0mL) is titrated with 176.5 mL 2.4 M NaOH to an equivalence point (the point where all the sulfuric acid is exactly neutralized). 2NaOH + H2SO4 -> 2H2O + Na2SO4 a) How many moles of Sulfuric acid were in the original 250.0 mL? moles of H2SO4 = b) What was the concentration of Sulfuric acid in the original 250.0 mL sample? Molarity of Sulfuric acid =
Standardization of NaOH solution experiment: A 0.75 g sample of pure acid KHP was titrated to phenolphthalein endpoint using 45.34 ml NaOH of unknown concentration. The formula weight of pure KHP is 204.22g/mol. Write the chemical equation for the neutralization reaction, indicate the color change of the indicator at the endpoint, and calculate molarity of the NaOH solution. Show your work. 1. Chemical equation ------------- 2. Endpoint color change ---- 3. NaOH molarity --------- Determine percent purity of impure KHP...