a)
df(regression)=2
df(residual)=10-2-1=7
SS(residual)=1.7621-0.1.88=0.1179
MS=SS/df
F=0.8811/0.0168=52.3100
t statistic=b1/sb1
p-value=tdist(t,7,2)
df | SS | MS | F | significance F | |
Regression | 2 | 1.7621 | 0.8811 | 52.3100 | 0.0000 |
residual | 7 | 0.1179 | 0.0168 | ||
Total | 9 | 1.88 | |||
Coefficients | standard error | t stat | p-value | ||
Intercept | -1.4053 | 0.4848 | -2.8987 | 0.0230 | |
X1 | 0.0235 | 0.0087 | 2.7011 | 0.0306 | |
X2 | 0.0049 | 0.0011 | 4.4545 | 0.0030 |
b)
p-value is less than 0.05,so regression model is significant.
c)
R^2=1.7621/1.88=0.9373
As,93.73% of the variation is explained by the model,so,yes,it provides good fit.
d)
As,p-value for both slope coefficients is less than 0.05,so both coefficients are significant.
The admissions officer for Clearwater College developed the following estimated regression equation relating the final college...
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