Homework Answers
Solution-
The equation can be written as:
Pb2+(aq) + 2 Cl-(aq) ------> PbCl2(s)
The moles of Pb2+ = moles of Pb(NO3)2 = volume * molarity of Pb(NO3)2
= (23.52/1000)* 0.6250 =0.0147 mol
The moles of Cl- = 2 x moles of Pb2+
= 2 *0.0147
= 0.0294 mol
Now the molarity of Cl- = moles of Cl-/volume of Cl- in L
= 0.0294/0.02500
= 1.176 M
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