Question

TOANE Cole lavancue 1. Given the balanced equation: (Show all work, 4 pts each except e, 5 points) 3 Cl2 + 6 KOH 5 KCI + KCIO3 + 3H20 a. How many moles of Cl2 have to react to produce 1.5 x 10-3 moles of KCIO3? b. How many grams of KCl are produced from the complete reaction of 3.0 m KOH? c. How many moles of Cl2 have to react to produce 5.40 x 103 g of H20? d. How many molecules of KOH have to react to produce 1.5 moles of H20? ILUKOH e. How many grams of KCl will be produced by the complete reaction of 2.54 x 10-3 g of Cl2?

Answer 1

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The yeachon is 5k Co k(203 t 34,0 a as per the veachon mole 6 KC90 Produce by 3 mcles af ( Imole of kco0 Paodure by3 mcles of ( 15X10 males of kcao, produce by3XISX10 males o l 2 4.5X103 mo KOH 5 moles of 6 mole praduces Imoles to preduces 5 males o KCI 3.0 mol of koH pioduces5X 3:0 meles p E5 mal o kC amount of KC2 Alo of male = KCe ynalas mass amaunt of kca 74.5 9mel 25 mol 74.5X 2.S amount of Pradede (86.29 K9

3 5.40X10 C) amount H,o molar masse mole 540X10 300 mol 3 mol of 0 poduce hy 3 mal oty poduce y 3 mel C9 I melef H,o 30omelo oho pradute b 2300 melof 300 mol of (9, IS repuised 3 mcl ,0 produce t mcl e'm,o praduce mel o picduce by 6XS mel ka 3 mol kaH S YeAUIved 1 mcl o koH Contan 3 mcles o kat Cordain =1.81X102 nclecede EGH