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1b Refer to this equation: 3 Cl2 + 6 KOH --> KCIO3 + 5 KCI + 3 H20 12.0 grams of Cl, is reacted with excess KOH. If 8.70 g of
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30lt 6KOH - KClO3+5kce +3720 3 moles of ch will produce s moles of kce I moles of cl will produce ş moles of kce 1 яната гk с

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