Solution:
Theoretical yield:
(M.W. of Cl2= 70.906 g/mol, M.W. of KCl= 74.55 g/mol)
Here, 3 mole (3 x 70.906 g = 212.718 g) of Cl2 give 5 mole (5 x 74.55 g = 372.75 g) of KCl.
12 g of Cl2 react with excess of KOH, hence theoretical yield is calculate as below.
Theoretical yield = (372.75 x 12) / 212.718 = 21.02 g
Now, Percent yield = (actual yield/ theoretical yield) x 100
= (8.7 / 21.02) x 100
= 41.3 %
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