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An empty 3.70 L steel vessel is filled with 2.00 atm of CH4(g) and 8.00 atm...

An empty 3.70 L steel vessel is filled with 2.00 atm of CH4(g) and 8.00 atm of O2(g) at 300 ∘C. A spark causes the CH4 to burn completely, according to the equation:
CH4(g)+2O2(g)→CO2(g)+2H2O(g) ΔH∘ = -802kJ

1. What is the final temperature inside the vessel after combustion, assuming that the steel vessel has a mass of 12.475 kg , the mixture of gases has an average molar heat capacity of 21J/(mol⋅∘C), and the heat capacity of steel is 0.499J/(g⋅∘C)?

2. What is the partial pressure of CO2(g) in the vessel after combustion?

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Answer #1

Angwer! - molep of CMA = PU RT 2.00 atm x 3.70L 0.082) Latm man k~X573k - 0.1573 mol Chalg) + 20219) - CO2(g) + 2 H2009) 64°=

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