The side which joins q1 to point P is hypotenuse whose length can be found using pythagoras theorem,
r = 6.403 cm
so,angle which electric field vector from q1 makes is
theta = arctan (4/5) = 38.65 degree
so,
Ex = 9e9*3.9e-6 * cos 38.65 / 0.064032 = 6.686e6 N/C
Ey = 9e9*3.9e-6 * sin 38.65 / 0.064032 = 5.347e6 N/C
E (total) = 8.561e6 N/C
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Ex (total) = 9e9*3.9e-6 * cos 38.65 / 0.064032 + 9e9*6.9e-6 * cos 38.65 / 0.064032 = 1.85e7 N/C
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Ey (total) = 9e9*3.9e-6 * sin 38.65 / 0.064032 - 9e9*6.9e-6 * sin 38.65 / 0.064032 = -4.113e6 N/C
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Total E at point P
E = sqrt (Ex2 + Ey2)
E = 1.895e7 N/C
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Now when both charges are equal, y component will cancel . Only x components will add up,
so,
E = 2 * 6.686e6 = 1.337e7 N/C
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