Question

A) How many grams of solute are needed to prepare 2.50 × 10² mL of 0.145 M CuSO₄?

B) A sample of crude oil contains 3.03 mM naphthalene, 11.8 mM methylnaphthalene, 24.4 mM dimethylnaphthalene, and 14.6 mMtrimethylnaphthalene. What is the total number of moles of all naphthalene compounds combined in 100.0 mL of the oil?

Answer 1

(1) schale = 2.50 x 10 ml, 0.145 z Lusou cusoy 256x10?x0.145 m moles 159.5g/mor. - 2.5x10²x0 145 x 103 moles = 2.5x10²x0.145x10² x 159.59 2.5x10²x0.145x 100 x 159.59 - 5.781g ③ Hap thay Hapthalene = 3.03 mm - 3.038103 x 0-1 moles Methyl napthalene = 11.8mm - 11.8x103 x0.1 males Dimethy) napthalen - 24:4014 2 24.48103 x 0.1 moles volume = loome 39.23x109 mores, = 0.12 = 3.923x10 3 mder