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A chemist adds 40.0mL of a 2.5/molL zinc nitrate ZnNO32 solution to a reaction flask. Calculate...

A chemist adds 40.0mL of a 2.5/molL zinc nitrate ZnNO32 solution to a reaction flask. Calculate the millimoles of zinc nitrate the chemist has added to the flask. Round to two significant digits.

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Answer #1

mole Concentrate of Zn(NO3), = 2.5 L Volume of the solution = 40.0 mL x 1000mL -0.0400L mole x0.0400L L Number of moles of Zn

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