The two plates of a capacitor hold +2500 μC and -2500 μC of charge, respectively, when the potential difference is 940 V .
What is the capacitance?
Solution)
Given,
Charge, Q=2500*10^-6 C
Voltage, V=940V
We know, Capacitance, C=Q/V=(2500*10^-6)/(940)
C=2.65*10^-6 F (Ans)
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The two plates of a capacitor hold +2500 μC and -2500 μC of charge, respectively, when...
The two plates of a capacitor hold +2500 μC and -2500 μC of charge, respectively, when the potential difference is 940 V What is the capacitance?
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