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In an electric shaver, the blade travels a total distance of 2.4 mm each cycle in simple harmonic motion, with frequency 86 Hz. Find (a) the amplitude (in mm), (b) the maximum blade speed, and (c) the magnitude of the maximum blade acceleration.
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Answer #1

(A) amplitude = 2.4 / 2 = 1.2 mm

(B) vmax = Aw = 2\piAf

vmax = 0.6484 m/s

(C) amax = Aw2 = 350.37 m/s2

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