The blade of an electric shaver vibrates in a simple harmonic
motion with a frequency 195.0 Hz over a distance 3.6 mm.
What is the amplitude of vibration?
Tries 0/10 |
What is the maximum blade speed?
Tries 0/10 |
What is the magnitude of the maximum blade acceleration?
The blade of an electric shaver vibrates in a simple harmonic motion with a frequency 195.0...
15) In an electric shaver, the blade moves back and forth over a stance of 2.0 mm in simple harmonic motion, with frequency 100 Hz. Find (a) the amplitude, (b) the maximum blade speed, and (c) the magnitude of the maximum blade acceleration. 20 An oscillating block-spring system has a mechanical energy of 2.00 J, an amplitude of 10.0 cm, and a maximum speed of 0.800 m/s. Find (a) the spring constant, (b) the mass of the block, and (c)...
In an electric shaver, the blade travels a total distance of 2.4 mm each cycle in simple harmonic motion, with frequency 86 Hz. Find (a) the amplitude (in mm), (b) the maximum blade speed, and (c) the magnitude of the maximum blade acceleration.
In an electric shaver, the blade moves back and forth over a distance of 2.0 mm. The motion is simple harmonic, with frequency 110 Hz. (a) Find the amplitude. mm (b) Find the maximum blade speed. m/s (c) Find the maximum blade acceleration. m/s2
2) In an electric shaver, the blade moves back and forth over a distance of 2.0 mm in simple harmonic motion, with frequency 120 Hz. Find (a) an expression for the blade's position as a function of time, (b) the maximum blade speed, and (C) the magnitude of the maximum blade acceleration.
An object attached to a spring vibrates with simple harmonic motion as described by the figure below. * (cm) 2.00 1.00 HA 0. 003 4 -1.00 -2.00 (a) For this motion, find the amplitude. cm (b) For this motion, find the period. S (c) For this motion, find the angular frequency. rad/s (d) For this motion, find the maximum speed. cm/s (e) For this motion, find the maximum acceleration. cm/s2
Question 1 1 21 Define simple harmonic motion (SHM). a) b) A steel rule is clamped to the end of a table, so that a large section overhangs the edge of the table. The free end of the rule vibrates with SHM when it is pulled down 30.5 mm and released. The frequency of the vibration is 16.0 Hz. i. Determine the time period of the vibration. I 2 1 i. Determine the maximum speed of the free end of...
A 15.5 kg mass vibrates in simple harmonic motion with a frequency of 17.73 Hz. It has a maximum displacement from equilibrium of +13.2 cm at time, t = 0.00 s. The displacement from equilibrium of the mass at time, t = 1.25 s is cm.
A 0.05kg particle moves in simple harmonic motion with a frequency of 20.0 Hz and an amplitude of 25.0 cm red 5.00 an (a) Through what total distance does the particle move during five cycle of its motion? (b) What is its maximum speed? Where does that occur? (c) Find the maximum acceleration of the particle. Where does that occur? Please write down the full working and indicate your answers for a) b) c) clearly Paragraph B IEE (a)
A particle moves in simple harmonic motion with a frequency of 3.80 Hz and an amplitude of 5.50 cm. (a) Through what total distance does the particle move during one cycle of its motion? cm (b) What is its maximum speed? cm/s Where does this maximum speed occur? as the particle passes through equilibrium at maximum excursion from equilibrium exactly halfway between equilibrium and maximum excursion none of these (c) Find the maximum acceleration of the particle. m/s^2 Where in...
Check my work Problem 19.002 - Frequency and velocity of a particle in simple harmonic motion A particle moves in simple harmonic motion. Knowing that the amplitude is 0.24 in, and the maximum acceleration is 225 ft/s, determine the maximum velocity of the particle and the frequency of its motion. points (8 03:40:34 The maximum velocity of the particle is ft/s, and the frequency of its motion is Hz. eBook Hint Print References