Question

Consider the following equation ZBrCl3ig) - Brzig) + 3Cl2 lg) reaction The equilibrium in was in a 4.0 Liter O Liter vessel t

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Answer #1

Ans :- Option (b) " 6 " is the correct answer

Explanation :-

Given,

Number of moles of BrCl3 (g) at equilibrium stage = 2.0 mol

Number of moles of Br2(g) at equilibrium stage = 6.0 mol

Number of moles of Cl2 (g) at equilibrium stage = 4.0 mol

and

Volume of the vessel = 4.0 L

As,

Molarity = Number of moles / Volume of the solution in L

So,

Molarity of BrCl3 (g) at equilibrium stage = 2.0 mol / 4.0 L = 0.5 M

Molarity of Br2 (g) at equilibrium stage = 6.0 mol / 4.0 L = 1.5 M

and

Molarity of Cl2 (g) at equilibrium stage = 4.0 mol / 4.0 L = 1.0 M

Given, reaction in equilibrium stage is :

2 BrCl3 (g) <---------------------------> Br2 (g) + 3 Cl2 (g)

Expression of equilibrium constant (Kc) :

Equilibrium constant (Kc) is the ratio of product of the molar concentration of products to the product of the molar concentration of reactants raise to the power stoichiometric coefficient at equilibrium stage of the reaction.

Kc = [Br2].[Cl2]3 / [BrCl3]2

Substitute the values in this equation :

Kc = (1.5 M).(1.0 M )3 / (0.5 M)2

On solving

Kc = 6 M2

Equilibrium constant (Kc) = 6

Hence, option (b) is the correct answer.

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