Ans :- Option (b) " 6 " is the correct answer
Explanation :-
Given,
Number of moles of BrCl3 (g) at equilibrium stage = 2.0 mol
Number of moles of Br2(g) at equilibrium stage = 6.0 mol
Number of moles of Cl2 (g) at equilibrium stage = 4.0 mol
and
Volume of the vessel = 4.0 L
As,
Molarity = Number of moles / Volume of the solution in L
So,
Molarity of BrCl3 (g) at equilibrium stage = 2.0 mol / 4.0 L = 0.5 M
Molarity of Br2 (g) at equilibrium stage = 6.0 mol / 4.0 L = 1.5 M
and
Molarity of Cl2 (g) at equilibrium stage = 4.0 mol / 4.0 L = 1.0 M
Given, reaction in equilibrium stage is :
2 BrCl3 (g) <---------------------------> Br2 (g) + 3 Cl2 (g)
Expression of equilibrium constant (Kc) :
Equilibrium constant (Kc) is the ratio of product of the molar concentration of products to the product of the molar concentration of reactants raise to the power stoichiometric coefficient at equilibrium stage of the reaction. |
Kc = [Br2].[Cl2]3 / [BrCl3]2
Substitute the values in this equation :
Kc = (1.5 M).(1.0 M )3 / (0.5 M)2
On solving
Kc = 6 M2
Equilibrium constant (Kc) = 6 |
Hence, option (b) is the correct answer.
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