The square in the reaction equation is an equilibrium sign. Consider the following reaction: 2NOBr(g) 2NO(g)...
A student ran the following reaction in the laboratory at 295 K: 2NO(g) + Br2(g) <---> 2NOBr(g) When she introduced 0.153 moles of NO(g) and 0.123 moles of Br2(g) into a 1.00 liter container, she found the equilibrium concentration of NOBr(g) to be 0.117 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = ____ The equilibrium constant, Kc, for the following reaction is 6.50×10-3 at 298K. 2NOBr(g) <---> 2NO(g) + Br2(g) If an equilibrium mixture of...
The equilibrium constant, Kc, for the following reaction is 6.50×10-3 at 298K. 2NOBr(g) 2NO(g) + Br2(g) If an equilibrium mixture of the three gases in a 11.1 L container at 298K contains 0.376 mol of NOBr(g) and 0.396 mol of NO, the equilibrium concentration of Br2
(1). The equilibrium constant, Kp, for the following reaction is 1.80×10-2 at 698K. 2HI(g) =H2(g) + I2(g) If an equilibrium mixture of the three gases in a 15.5 L container at 698K contains HI at a pressure of 0.399 atm and H2 at a pressure of 0.562 atm, the equilibrium partial pressure of I2 is atm. (2). Consider the following reaction: PCl5(g) =PCl3(g) + Cl2(g) If 1.17×10-3 moles of PCl5, 0.217 moles of PCl3, and 0.351 moles of Cl2 are at...
A student ran the following reaction in the laboratory at 254 K: 2NO(g) + Br2(g) ⇌ 2NOBr(g) When she introduced 0.185 moles of NO(g) and 0.130 moles of Br2(g) into a 1.00 liter container, she found the equilibrium concentration of NOBr(g) to be 0.152 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =
The equilibrium constant, Kp, for the following reaction is 0.160 at 298K. 2NOBr(g) 2NO(g) + Br2(g) If an equilibrium mixture of the three gases in a 19.9 L container at 298K contains NOBr at a pressure of 0.297 atm and NO at a pressure of 0.251 atm, the equilibrium partial pressure of Br2 is ? atm.
Consider the following reaction where K. = 154 at 298 K: 2NO(g) + Br2(g) = 2NOBr(g) A reaction mixture was found to contain 2.86x10-2 moles of NO(g), 3.93x10-2 moles of Br2(g) and 8.83x10-2 moles of NOBr(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: 1. In order to reach equilibrium NOBr(g) must be consumed. 2. In order to reach equilibrium K, must increase. 3. In order to reach equilibrium NO must be...
A student ran the following reaction in the laboratory at 225 K: 2NOBr(g) 2 2NO(g) + Brz(g) When she introduced 0.198 moles of NOBr(g) into a 1.00 liter container, she found the equilibrium concentration of Br2(g) to be 1.89x10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =
Consider the following reaction where K. = 154 at 298 K: 2NO(g) + Br2(g) = 2NOBr(g) A reaction mixture was found to contain 4.48 102 moles of NO(g), 3.92x102 moles of Brg(e) and 7.91x102 moles of NOBr(g), in a 1.00 Liter container Indicate True (I) or False (E) for each of the following: 1. In order to reach equilibrium NOBr(e) must be consumed, 2. In order to reach equilibrium Ke must increase 3. In order to reach equilibrium NO must...
Consider the following reaction where Kc = 154 at 298 K: 2NO(g) + Br2(g) 2NOBr(g) A reaction mixture was found to contain 2.42×10-2 moles of NO(g), 4.38×10-2 moles of Br2(g) and 9.68×10-2 moles of NOBr(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: 1. In order to reach equilibrium NOBr(g) must be produced. 2. In order to reach equilibrium Kc must decrease. 3. In order to reach equilibrium NO must be produced....
Consider the following reaction where Kc = 154 at 298 K. 2NO(g) + Br2(g) 2NOBr(g) A reaction mixture was found to contain 4.44×10-2 moles of NO(g), 3.68×10-2 moles of Br2(g) and 7.92×10-2 moles of NOBr(g), in a 1.00 liter container. Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? The reaction quotient, Qc, equals . The reaction A. must run in the forward direction to reach equilibrium. B. must run in the...