Question

Consider the following reaction where K. = 154 at 298 K: 2NO(g) + Br2(g) = 2NOBr(g) A reaction mixture was found to contain 2.86x10-2 moles of NO(g), 3.93x10-2 moles of Br2(g) and 8.83x10-2 moles of NOBr(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: 1. In order to reach equilibrium NOBr(g) must be consumed. 2. In order to reach equilibrium K, must increase. 3. In order to reach equilibrium NO must be produced. 4. Qc is greater than Kc. 5. The reaction is at equilibrium. No further reaction will occur. -

Answer 1

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so! ! Here the reaction is, NO) + BY, 2NOBY cal (4) volume - 1L NOg} = 2.86x102 moles Br2.(0) = 3.93 x 102 moles NOBY (4) = 8.83 x 10.2 moles Temp. = 298k Ke=154 we know at equibrium [NOBY]" [no] [Br.] but if system is not in equilibrium then Qc = [NOBV) (8.83x102 [NO IT Bv] (2086810*) (3.93x10 %) 242.54 Here ke < Od 1. TRUE :- The decrease the value of Qcwe need to conjume NOBY (9) FALSE - K is equilibrium constant and it is constant for given temprature and pressure conditions. hence it will not increase or decrease Production of NO will decrease o 3TRUE - Produ - 9 TRUE is greater than ka mtu : The reacti The reaction is not at equlibrium as k, #9 FALSE