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3. The Pb2+ ion has a hydrated radius of 450 pm. What is the activity of...
ID03/2 hul the lune strength is due solely to the O 0.562 7.5 x 10-3 O 5.2 x 10-3 4.2 x 10-3 4. Magnesium fluorid...
ID03/2 hul the lune strength is due solely to the O 0.562 7.5 x 10-3 O 5.2 x 10-3 4.2 x 10-3 4. Magnesium fluoride (MgF2) is a sparingly soluble salt. It has Kp = 7.4x10-9. Calculate the concentration of fluoride ion in a saturated solution of MgF,. O 1.2 x 10-3 M O 2.5 x 10-3 O 7.4 x 10-9 O 6.3 x 10-5 5. Consider the reaction Sr(s) + FeOH(aq) + H2O + (aq) Sr2+ (aq) + Fe(s)...
Consider the equilibrium shown. PbBr_(s) = Pb2 + (aq) + 2 Br" (aq) Kop = 2.10...
Consider the equilibrium shown. PbBr_(s) = Pb2 + (aq) + 2 Br" (aq) Kop = 2.10 x 10-6 Determine the concentrations of Pb2+ and Br" in a saturated solution of PbBr, in pure water (assume = 0M). [Pb2+1 = 0.00806 M [Br") = 0.01612 Determine the concentrations of Pb2+ and Br" in a saturated solution of PbBr, in a solution with an ionic strength of 0.010 M [Pb2+] = 0.010 [Br") = 0.02 Determine the concentrations of Pb²+ and Br"...
Consider the equilibrium shown. PbBr (s)Pb2 (aq) +2 Br (aq) Kp 2.10 x 10-6 Determine the...
Consider the equilibrium shown. PbBr (s)Pb2 (aq) +2 Br (aq) Kp 2.10 x 10-6 Determine the concentrations of Pb + and Br in a saturated solution of PbBr, in pure water (assume u = 0 M). Pb2 +10.0375 М [Br]= 0.0749 м Determine the concentrations of Pb+ and Br in a saturated solution of PbBr, in a solution with an ionic strength of 0.010 M. Pb2+1 0.010 М Br]= 0.02 м Determine the concentrations of Pb+ and Br in a...
Please help. i will rate What is the activity coefficient for each ion at the given ionic strength at 25°C? Activi...
Please help. i will rate
What is the activity coefficient for each ion at the given ionic strength at 25°C? Activity coefficients at various ionic strengths can be found in this table. so - (x = 0.1 M) Y = .476 AP (4 = 0.01 M) y = .348 Dy! (u = 0.05 M) = 0,0941 (CH,CH), NH* (4 m (0.001 M) ¥m (0,9635 Ion Use the Debye-Hückel equation to calculate the activity coefficient of each ion at the given...
Hint Check Answe estion 29 of 32 > Consider the equilibrium shown. PbBr(s) = Pb2+ (aq)...
Hint Check Answe estion 29 of 32 > Consider the equilibrium shown. PbBr(s) = Pb2+ (aq) + 2 Br" (aq) Kyp = 2.10 x 10-6 Determine the concentrations of Pb2+ and Brin a saturated solution of PbBr, in pure water (assume u = 0 M). (PB2+1 = M [B") = Determine the concentrations of Pb2+ and Br“ in a saturated solution of PbBr, in a solution with an ionic strength of 0.010 M [Pb2+) = B- Determine the concentrations of...
c. Consider lead iodide, Pblz. Ignoring ion pairing, but taking to activity into account, what is...
c. Consider lead iodide, Pblz. Ignoring ion pairing, but taking to activity into account, what is the concentration of Pb2+ in a sodium nitrate solution with an ionic strengths of 0.01 M? (3 pts)
20. Ethylenediaminetetraacetate (EDTA4-) is used as a complexing agent in chemical analysis. Solu...
20. Ethylenediaminetetraacetate (EDTA4-) is used as a complexing agent in chemical analysis. Solutions of EDTA4- are used to treat heavy metal poisoning by removing the heavy metal in the form of a soluble complex ion. The complex [Pb(EDTA]2- has Kf = 1.1 x 1018. a. Calculate the concentration of Pb2+ in a saturated solution of Pb(OH)2, Ksp = 1.2 x 10-15. b. Calculate the concentration of Pb2+ in a saturated solution of Pb(OH)2 buffered at pH 13.00 c. Calculate the...
(3) What affect does the charge of the ion in solution have on the activity coefficient?...
(3) What affect does the charge of the ion in solution have on the activity coefficient? How does this effect change as a function of the ionic strength (u)? (4) Does the activity coefficient depend on whether the ion is a cation or an anion?
Question 4 07 1.5 pts What is the concentration of Pb2+ in a saturated solution of...
Question 4 07 1.5 pts What is the concentration of Pb2+ in a saturated solution of PbCl2 in 0.10 M KCl solution. (Ksp = 1.4 x 108)? Why is [Pb2') in this question (smaller/larger) than in Question 3? Hint: What is the initial [CI] before PbCl2 is dissolved? because the presence of chloride ion prevents the dissolution 1.4 x 10M of PbCl2 1.5 x 10M same as in Question 3 1.4 x 10-M, because the presence of chloride ion slows...
22. Which of the following pairs of compounds and ions could be used to form a...
22. Which of the following pairs of compounds and ions could be used to form a buffer solution? (a) 0.10 M HCl and 0.10 M Naci (b) 0.10 M NH4Cl and 0.10 M NH3 (c) 0.10 M HNO2 and 1.0 x 10'M NaNO, 23. An activity coefficient (a) measures the deviation of behavior of ions from ideality. (b) is obtained by multiplying the concentration of a solution times the ionic strength. (c) replaces the concentration term in chemical calculations. It...
ID03/2 hul the lune strength is due solely to the O 0.562 7.5 x 10-3 O 5.2 x 10-3 4.2 x 10-3 4. Magnesium fluoride (MgF2) is a sparingly soluble salt. It has Kp = 7.4x10-9. Calculate the concentration of fluoride ion in a saturated solution of MgF,. O 1.2 x 10-3 M O 2.5 x 10-3 O 7.4 x 10-9 O 6.3 x 10-5 5. Consider the reaction Sr(s) + FeOH(aq) + H2O + (aq) Sr2+ (aq) + Fe(s)...
Consider the equilibrium shown. PbBr_(s) = Pb2 + (aq) + 2 Br" (aq) Kop = 2.10 x 10-6 Determine the concentrations of Pb2+ and Br" in a saturated solution of PbBr, in pure water (assume = 0M). [Pb2+1 = 0.00806 M [Br") = 0.01612 Determine the concentrations of Pb2+ and Br" in a saturated solution of PbBr, in a solution with an ionic strength of 0.010 M [Pb2+] = 0.010 [Br") = 0.02 Determine the concentrations of Pb²+ and Br"...
Consider the equilibrium shown. PbBr (s)Pb2 (aq) +2 Br (aq) Kp 2.10 x 10-6 Determine the concentrations of Pb + and Br in a saturated solution of PbBr, in pure water (assume u = 0 M). Pb2 +10.0375 М [Br]= 0.0749 м Determine the concentrations of Pb+ and Br in a saturated solution of PbBr, in a solution with an ionic strength of 0.010 M. Pb2+1 0.010 М Br]= 0.02 м Determine the concentrations of Pb+ and Br in a...
Please help. i will rate
What is the activity coefficient for each ion at the given ionic strength at 25°C? Activity coefficients at various ionic strengths can be found in this table. so - (x = 0.1 M) Y = .476 AP (4 = 0.01 M) y = .348 Dy! (u = 0.05 M) = 0,0941 (CH,CH), NH* (4 m (0.001 M) ¥m (0,9635 Ion Use the Debye-Hückel equation to calculate the activity coefficient of each ion at the given...
Hint Check Answe estion 29 of 32 > Consider the equilibrium shown. PbBr(s) = Pb2+ (aq) + 2 Br" (aq) Kyp = 2.10 x 10-6 Determine the concentrations of Pb2+ and Brin a saturated solution of PbBr, in pure water (assume u = 0 M). (PB2+1 = M [B") = Determine the concentrations of Pb2+ and Br“ in a saturated solution of PbBr, in a solution with an ionic strength of 0.010 M [Pb2+) = B- Determine the concentrations of...
c. Consider lead iodide, Pblz. Ignoring ion pairing, but taking to activity into account, what is the concentration of Pb2+ in a sodium nitrate solution with an ionic strengths of 0.01 M? (3 pts)
(3) What affect does the charge of the ion in solution have on the activity coefficient? How does this effect change as a function of the ionic strength (u)? (4) Does the activity coefficient depend on whether the ion is a cation or an anion?
Question 4 07 1.5 pts What is the concentration of Pb2+ in a saturated solution of PbCl2 in 0.10 M KCl solution. (Ksp = 1.4 x 108)? Why is [Pb2') in this question (smaller/larger) than in Question 3? Hint: What is the initial [CI] before PbCl2 is dissolved? because the presence of chloride ion prevents the dissolution 1.4 x 10M of PbCl2 1.5 x 10M same as in Question 3 1.4 x 10-M, because the presence of chloride ion slows...
22. Which of the following pairs of compounds and ions could be used to form a buffer solution? (a) 0.10 M HCl and 0.10 M Naci (b) 0.10 M NH4Cl and 0.10 M NH3 (c) 0.10 M HNO2 and 1.0 x 10'M NaNO, 23. An activity coefficient (a) measures the deviation of behavior of ions from ideality. (b) is obtained by multiplying the concentration of a solution times the ionic strength. (c) replaces the concentration term in chemical calculations. It...
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