by the linear momentum conservation
suppose speed of mass 1 kg = v1 and mass 7 kg = v2 after collision
Pi =Pf
1*5 + 7*0 = 1*v1 + 7*v2
v1 + 7v2 = 5 ........ i
v1 = 5- 7v2 plug this value in ii
by energy conservation
1/2*1*5^2 = 1/2*1*v1^2 +1/2*7*v2^2
v1^2 + 7v2^2 = 25 ...... ii
]from equation i and ii
v1 = 3.75 m/s in left
v2 = 1.25 m/s in right
fraction of energy tranferred =
7 kg mass energy / Total energy before collision
= 1/2*7*1.25^2 / ( 1/2*1*5^2) =
= 0.4375
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