Question

you need to prepare 100 mL of 5.00%(w/v) glu solution using anhydrous glu (mw 180.000) which has an assay value of 97.6%. How many grams of glu do u need?

Answer 1

We have, w/ V % solution  = (mass of solute (gm) ÷ volume of solution (ml)) × 100

We need to prepare 100 mL of 5.00%(w/v) glu solution using anhydrous glu (mw 180.000); Glucose has an assay value of 97.6%.

5 % of 100 = 5.00

We need 5.00 gm of Anhydrous Glucose in solution, but our glucose has assay of 97.6% :

for ensuring 5 % of glucose by w/V present in solution we will need :

(100/97.6) * 5 g = 5.1229 gm of given anhydrous glucose (mw 180.000).