Question

2. How many ml of a 50% w/v acetic acid solution are required to prepare 1 L of 5% w/v acetic acid? 3. How many ml of concent

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Answer #1

2)

Answer

100ml

Explanation

Dilution formula is as follows

C1×V1 = C2 × V2

C1 = Initial solution concentration , 50% w/v

V1 = Initial solution volume , ?

C2 = Final solution concentration, 5%

V2 = Final solution volume , 1L

V1 = C2×V2/C1

= 5% × 1L / 50%

= 0.1L

= 100ml

3)

Answer

18.99ml

Explanation

Normality of concentrated HNO3(C1) = 15.8N

Volume of concentrated HNO3 required(V1) = ?

Normality of final solution required(C2) = 0.15N

Volume of concentrated HNO3 required(V1) = 2L

V1 = C2 × V2/C1

= 0.15N × 2L /15.8N

= 0.01899L

= 18.99ml

4)

Answer

100ml

Explanation

C1 = 20% w/v

V1 = ?

C2 = 2.5 %

V2 = 800ml

V1 = 2.5% w/v × 800ml/20% w/v

= 100ml

5)

Answer

2 \muL

Explanation

C1 = 5X

V1 = ?

C2 = 1X

V2 = 10\muL

V1 = 1X × 10\muL /5X

V1 = 2\muL

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