Question

Partner: 1. How many grams of NiCl2:6H20 will be used to prepare a 0.0350 M. 500.0 mL of NiCl! solution? 2. How many milliliters of 12.0 M HCl are required to prepare a 2.00 M 250.0 mL of HCI solution? 3. 15.00 mL of an unknown concentrated solution was diluted to 100.0 mL. Then 35.00 mL of this diluted acid solution was titrated with 23.24 mL of 0.3724 M standard NaOH solution to reach the ending point. What is the molarity of the original concentrated acid solution?

Answer 1

Nid,- 6H2o Nicz + 6H₂O one mote when one mole Nich- 6 to heated, then Nich is for med. Molecular mass of Nice6420 = = 129.6 g moral on sooml 0.035 M Niche Contains soon (60ome = 0.0175 mol Niche required Nich=640 = 0.01754 929.6g - 3,2689 Initial concentration af Hel = = 12.0M. final concentration of Hal= S₂=2.0m final volume of Hel = 250.ome. i. Initial volume = v= ?? we know that vis= V2 S2 v = V2 S2 – 250 mx 2.0M 12.0M 41.67 m2. - to prepare 41.67 ml of 12.0M All required 2 800 me 2.0M HR solution.

(3 volume of the dilleited acid = v= 35.00u. strength of the distuted acid=S, 22 Strength of Naot solution - Sa=0.37UM Volume of Nath solution = ₂ = 23.24 m2 We know, vs. = V₂ S2 in S, V. S2 23.22 me x or 374M V 35-00 me = 0.248 M.. . Strength of the dillited acid = 0.248 M. Volume of the dilluted acid prepared = 100.0mL. votume of the original and taken = 15.00m2 : strength of the original acid 100m2 x 0.248M 15.oome - 1.66 M. Strength of the original and = 1.6667