The heat of solution of potassium acetate (KC2H3O2) in water is -15.30 kJ/mol.
Heat of Solution
The heat of solution of potassium acetate (KC2H3O2) in water is -15.30 kJ/mol.
If 16.80 g of KC2H3O2(S) is dissolved in 525.0 mL of water that is initially at 22.70 °C, what will be the final temperature in degrees Celcius) of the resulting aqueous solution?
(Assume no heat exchange with the surroundings.)
_______ ℃
Homework Answers
no of moles of KC2H3O2 = W/G.M.Wt
= 16.8/98.15 = 0.17116 moles
H
= -15.3KJ/mole
= -15.3KJ/mole*0.17116moles
= -2.618748KJ
= -2618.748J
q = 2618.748J
mass of water = volume * density
= 525*1 = 525g
q = mcT
2618.748 = 525*4.184*(t-22.7)
t = 240C
The final temperature = 240C
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The heat of solution of potassium acetate (KC2H3O2) in water is -15.30 kJ/mol.
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