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Prelab: 1. The molar heat of solution of ammonium nitrate is +25.7 kJ/mol. Assuming the specific heat of the resulting soluti

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Answer #1

1)

molar heat of solution = +25.7 kJ/mol

mass of water = 55.0 g

mass of NH4NO3 = 3.0 g

moles of NH4NO3 = 3.0 / 80.04 = 0.0375 mol

delta H = - Q / n

25.7 = - Q / 0.0375

Q = - 0.963 kJ = 963 kJ

Q = m Cp dT

963 = - 55 x 4.184 x (Tf - 22.9)

Tf = 18.7 oC

final temperature = 18.7 oC

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