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Heat Flow and Calorimetry Prelab Questions Section: Name: 1. Prepare for It! Prelab Question A A 235.0 g sample of metal is h


Rearranging the equation to solve for molar mass gives the following: 25 mol C мм having units of g/mol (equation 5) specific
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Answer #1

1) w represent water and m represents metal

Heat taken by water = heat given by metal

M(w) * S(w) * Delta T(w) = M(m) * S(m) * Delta T(m)

50 * 4.18 * (30.5 - 20.5) = 235 * S * (100 - 30.5)

S = 0.128 J/°C g ....Answer

2)

Heat or enthalpy of solution (H) = m * s * Delta T

H = (3.1+57.9) * 4.18 * (36.6 - 22.5) = 3595.22 J ...Answer

Enthalpy per gram = 3595.22/3.1 = 1159.75 J/g ....Answer

Moles of NaOH = mass/molar mass = 3.1/40 = 0.0775 moles

Thus, enthalpy per mole = 3595.22/0.0775 = 46389.91 J/mol = 46.39 KJ/mol ...Answer

Let me know if any doubts.

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