Here we apply concept of series RLC circuit with AC supply. We apply phasor diagram concept to solve the circuit.
The RCL series circuit shown below (R=0.04 2, L=5.00uH) is in resonance with a source that...
The circuit shown in Figure 3 below shows a R-L-C series circuit with components R= 50 , L = 1 H, and C= 250 uF. This circuit is connected in series to an AC current source ( il ) where instantaneous current is given by it = 28.29 Sin (100t) A. B + VR- C + VC - D ).4C Current source Figure 3 (a) Draw the circuit diagram for this circuit and mark the impedances (3 marks) (b) What...
(45 pts.) For the circuit shown, R = 50.0 Ω, L 95.0 mH, and C-70.0 pC The power source has 5, 65.0 V rms and a frequency of 40.0 Hz. a. What is the value of XL? b. What is the value of Xc? c. What is the value of Z? d. What is the rms current? e. What is the rms voltage across the resistor? f. What is the rms voltage across the inductor? g. What is the rms...
Chapter 23, Problem 35 A series RCL circuit is at resonance and contains a variable resistor that is set to 12a. The power dissipated in the circuit is i,60 w. Assuming that the voltage remains constant, how much power is dissipated when the variable resistor is set to 690Ω7 Note: The ac current and voltage are rms values and powers an average ra e iness indicated otherwise Number Units the tolerance is +/-596
In a series R-L-C circuit, L = 0.190 H , C = 84.5 μF and the voltage amplitude of the source is 290 V . Part A What is the resonance angular frequency of the circuit? ω0 = rad/s SubmitMy AnswersGive Up Part B When the source operates at the resonance angular frequency, the current amplitude in the circuit is 0.610 A . What is the resistance R of the resistor? R = Ω SubmitMy AnswersGive Up Part C At...
An L-R-C series circuit L = 0.124 H , R = 245 Ω , and C = 7.28 μF carries an rms current of 0.451 A with a frequency of 394 Hz A)What is the phase angle?' F)What is the average rate at which electrical energy is dissipated (converted to other forms) in the capacitor? B)What is the power factor for this circuit? G)in the inductor? C)What is the impedance of the circuit? D)What is the rms voltage of...
1. A resistor R and capacitor care connected in series with an AC voltage source with frequency f and maximum voltage Vo. a. Find the complex impedance (in the form Z = R + jX). If the impedance is written in polar form (Z = Zejº), find expressions for Z and Ⓡ. Write your answers in terms of the variables R, C, and o(= 21f). b. If the voltage source is described by the phasor V = V, ejwt, and...
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 190 V, and the frequency is f = -0 Hz. Given that L = 0.6 H, C = 75 uF, and VR = 20 V, find: a) I (rms); I = b) R; R= c) VL (rms); VL = d) Vc (rms). Vc =
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 220 V, and the frequency is f = Hz. Given that L 0.35H, C = 45 pF, and VR = 75 V. find: 260 2 a) I (rms); A b) R; R 22 c) VL (rms); VL V d) Vc (rms). Vc V
(0 points) In an RLC series circuit, the rms potential difference provided by the source is V = 200 V, and the frequency is f 290 Hz. Given that L = 0.25 H, C = 60 uF, and VR = 65 V, find: = 7T a) I (rms); I = A b) R; R= 12 c) VL (rms); Vi V d) Vc (rms). Vc = V
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 150 V, and the frequency is f 240 Hz. Given that L = 0.1 H, C = 40 uF, and VR = 20 V, find: T a) I (rms); I A b) R; R 12 c) VL (rms); VL: V d) Vc (rms). Vc = V