Question

The circuit shown in Figure 3 below shows a R-L-C series circuit with components R= 50 , L = 1 H, and C= 250 uF. This circuit is connected in series to an AC current source ( il ) where instantaneous current is given by it = 28.29 Sin (100t) A. B + VR- C + VC - D ).4C Current source Figure 3 (a) Draw the circuit diagram for this circuit and mark the impedances (3 marks) (b) What is the peak current of current source (2 marks) (c) Calculate the RMS value of current source. (2 marks) (2 marks) (d) What is the angular frequency of AC current source? (e) What is the inductive reactance of the inductor? (2 marks) (f) What is the capacitive reactance of the capacitor? (2 marks) (g) What is the magnitude of the RMS voltage through the resistors (Vr)?(2 marks) (h) What is the magnitude of the RMS voltage through the inductor (VL)? (2 marks)

Answer 1

AND EUR 6 Accurrent اعوان اکرم - H . ملے وو - 28.29 Sim (louts Amp , w=100 gonfedance of corcuult. recetance of Lejwel reactance of controc joon o rren- reactance of ca 100x 250 x 10-6 مجله w son - 400gr v3.100'y (b) pealt current of current source - is 28-29 sih loot imsin wel Here im- 28.29 Ang is the peak current e) Rins value of current source itome im 2018

Angulas frequency wa 100 sad see se reactance of inductor te-Owl - 100) & (f) Capacitive reactance X=-) – – 403 r. Rms voltage through. e resp der VR me = Long R u s-2000 - 20x50 - 1000 Golf ch Russ voltage through the inductor mas que - dox loog - 2000) magnitude of urine - 2000 volt.
use basic of kvl and find voltage across the each element