Homework Answers
1st calculate the heat required
Given:
m = 50 g
C = 4.184 J/g.oC
Ti = 25 oC
Tf = 30 oC
use:
Q = m*C*(Tf-Ti)
Q = 50.0*4.184*(30.0-25.0)
Q = 1046 J
Q = 1.046 KJ
This heart is supplied by C51H93O6
Mol of C51H93O6 required = total heat / heat produced per mol
= 1.046 / 3.022*10^4
= 3.46*10^-5 mol
Molar mass of C51H93O6,
MM = 51*MM(C) + 93*MM(H) + 6*MM(O)
= 51*12.01 + 93*1.008 + 6*16.0
= 802.254 g/mol
use:
mass of C51H93O6,
m = number of mol * molar mass
= 3.46*10^-5 mol * 8.023*10^2 g/mol
= 2.776*10^-2 g
Answer: 2.78*10^-2 g
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