Question

1. A researcher raises the temperature from 77.1 to 95.2 o C and finds that the...

1. A researcher raises the temperature from 77.1 to 95.2 o C and finds that the rate of the reaction doubles. What was the activation energy (in Joules) for this reaction? (R = 8.3145 J/molK).

2. The reaction A → B + C is zero order with respect to A. When [A]0 = 0.544 M, the reaction is 28 % complete at 91.5 min. Calculate the half-life for this reaction.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Q-1 71.1°C (350.1) 95.200 (368.2) en 2 Ea 8.314] : 3033x) 368. 2k 35o.lk mol-k * () 42. godine (souk 0.693 Eax 1.688x105 ta:

Add a comment
Know the answer?
Add Answer to:
1. A researcher raises the temperature from 77.1 to 95.2 o C and finds that the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • *A researcher raises the temperature from 60 to 77.9 o C and finds that the rate...

    *A researcher raises the temperature from 60 to 77.9 o C and finds that the rate of the reaction doubles. What was the activation energy (in Joules) for this reaction? (R = 8.3145 J/molK) *A researcher raises the temperature from 85.8 to 102.7 o C and finds that the rate of the reaction doubles. What was the activation energy (in kJ) for this reaction? (R = 8.3145 J/molK)

  • please help A researcher raises the temperature from 44.2 to 61.6 °C and finds that the...

    please help A researcher raises the temperature from 44.2 to 61.6 °C and finds that the rate of the reaction doubles. What was the activation energy in /mol) for this reaction? (R-8.3145 /mold mol

  • please help A researcher raises the temperature from 44.2 to 61.6°C and finds that the rate...

    please help A researcher raises the temperature from 44.2 to 61.6°C and finds that the rate of the reaction doubles. What was the activation energy in /mol) for this reaction? (R - 8.3145 /mol K) Imol

  • For the following first order reaction, the half-life is 28.3 and the [A]0 = 1.36. Calculate the rate constant.

    A.For the following first order reaction, the half-life is 28.3 and the [A]0  = 1.36. Calculate the rate constant.2A -> 3BB.Consider the following reaction. aA + bB -> cCwhose first and second half-lives are 38.2 and 19.1 minutes respectively. If the rate constant is equal to 0.2148 and [A]0 = 16.41, calculate the [A] at t 5.87 minutes.C.A researcher raises the temperature from 46.4 to 66 °C and finds that the rate of the reaction doubles. What was the activation energy (in...

  • 1. The reaction A → B + C is zero order with respect to A. When...

    1. The reaction A → B + C is zero order with respect to A. When [A]0 = 0.544 M, the reaction is 28 % complete at 91.5 min. Calculate the half-life for this reaction. 2. Consider the following reaction. Calculate the value of the rate constant.. 2 A + B →→ 2 C A B C Rate Trial 1 0.64 0.56 0.012 7.463 Trial 2 1.28 0.56 0.012 14.926    Trial 3 0.64 1.12 0.012 14.926 Trial 4 0.1...

  • Could I get help on part B 3a. A certain first-order reaction is 35.5% complete in...

    Could I get help on part B 3a. A certain first-order reaction is 35.5% complete in 4.90 minutes at 25°C. What is its rate constant e-kt K,=0.0895 min 64.5% min - 10 0.645 1.00 to = 8.95 x 100% 4.905 -0.0895 min 3b. If a first-order reaction has an activation energy of 104,600 J/mole and an A value of 5 x 10 sec !, at what temperature will the reaction have a half-life of 1 min? What about 30 days?

  • 1) 2) 3) The decomposition of dinitrogen tetroxide to nitrogen dioxide at 400°C follows first-order kinetics...

    1) 2) 3) The decomposition of dinitrogen tetroxide to nitrogen dioxide at 400°C follows first-order kinetics with a rate constant of 3.84 X10-3-1. Starting with pure N204, how many minutes will it take for 38.0% to decompose? Suppose the surface-catalyzed hydrogenation reaction of an unsaturated hydrocarbon has a rate constant of 0.374 M/min. The reaction is observed to follow zero-order kinetics. If the initial concentration of the hydrocarbon is 2.90 M, what is the half-life of the reaction in seconds?...

  • 1. If the rate constant of a reaction increases by 2.5 when the temperature is increased...

    1. If the rate constant of a reaction increases by 2.5 when the temperature is increased from 25 C to 34 C, then what is the activation energy (in kJ/mole) of the reactions? 2. If a reaction is first order with a rate constant of 4.48 x 10 ^ -2 sec ^-1, how long is required for 3/4 of the initial concentration of reactant to be used up? 3. Which statement is true or NOT regarding the experimental determination of...

  • . (a) If a first-order reaction has an activation energy of 104.6 kJ/mol and, in the...

    . (a) If a first-order reaction has an activation energy of 104.6 kJ/mol and, in the equation k = k0 exp (-Ea/RT), k0 has a value of 5×1013/s, at what temperature will the reaction have a half-life of (i) 1 h; (ii) 1 day? [Note: the value of R is 8.314 kJ/kmol·K.] (b) If the sterilization of a biomaterial was heating at 121°C for 5 min, it could only be heated at 111°C due to the failure of the heating...

  • A batch reactor operating at near room temperature, 25°C, is currently taking six hours to reach...

    A batch reactor operating at near room temperature, 25°C, is currently taking six hours to reach ninety percent conversion for an irreversible second-order liquid-phase reaction. Account the time to fill, empty, and clean the reactor, this allows one batch to be handled during an ei hour work shift. ing for ght- There is now pressure to cut the reaction time in half, to three hours, so two batches can be handled during a shift. When the reactor temperature is increased...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT