Calculate the pH of each of the following aqueous solutions.
0.0400 M malonic acid
0.0400 M monosodium malonate (sodium hydrogen malonate) [use the most accurate and the most approximate formulas and compare the two]
0.0400 M disodium malonate
pH= -log[H+]
ph= -log [normality]
pH= -log [molarity*valency]
malonic acid is divalent acid so valency=2
pH= -log [0.0400*2]
= 1.096
Monosodiukm malonate each mole will produce 1 hydrogen atom so
pH= pH= -log [0.0400*v1]
1.39
disodium malonate cannot give any hydrogen so its a salt and its pH=7
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