Question

In 2014, students in an advanced Statistics course at UC Berkeley conducted an anonymous survey about use of cognition-enhancing drugs among college males. One survey group of males included members from a fraternity, and the other survey of males group included no fraternity members.

The standard error formula for the difference between sample proportions is

pn(1-P) (1-p.) 介一命 V 十l:

Calculate the standard error for a survey comparing proportions of cognition-enhancing drug use of fraternity members to non-fraternity members, where p1 = 0.34, n1 = 141, p2 = 0.26, n2 = 98. Round all calculations to the thousandth decimal place.

Answer 1

The statistic software output for this problem is:

Two sample proportion summary hypothesis test: Pi : proportion of successes for population 1 P2: proportion of successes for population 2 P1-P2 : Difference in proportions Ho: P1 - P2 = 0 HA : P1 - P20 Hypothesis test results: Difference Count1 Totali Count2 Total2 Sample Diff. Std. Err. Z-Stat P1 - P2 47.94 141 25.48 98 0.08 0.060672178 1.3185615 P-value 0.1873

the standard error = 0.061