Question

Question 6 In 2014, students in an advanced Statistics course at UC Berkeley conducted Type numbers in the boxes. an anonymous survey about use of cognition-enhancing drugs among college 10 points males. One survey group of males included members from a fraternity, and the other survey group of males included no fraternity members. The standard error formula for the difference between sample proportions is "Bi-Py= P, (1-P) P (1-P) + 11 122 Calculate the standard error for a survey comparing proportions of cognition-enhancing drug use of fraternity members to non-fraternity members, where pı = 0.32, n = 125, P2 = 0.2, n2 = 98. Round all calculations to the thousandth decimal place.

Answer 1

86 niz 125 na z 98 Piz 0-32, Pe=0.2 op - p2 = pili-pi) + p2/1-82) ni 0:32(0.68) + 0.210.8). 125 0.05808143 98 0.058 05 The two proportions are proportion of females being being past smokers 42 139 p2 = Proportion of males being past smokers 52' 101 Pi-P2 = 42 -0.2126932 52 101 ~ -0.2127 139