Question

In 2014, students in an advanced Statistics course at UC Berkeley conducted an anonymous survey about use of cognition-enhancing drugs among college males. One survey group of males included members from a fraternity, and the other survey group of males included no fraternity members. The standard error formula for the difference between sample proportions is Obi-=V P (1-P), P (1-P) -+ ni n2

Answer 1

SOLUTION-

$\sigma _{\hat{p_1}-\hat{p_2}}=\sqrt{p_1(1-p_1)/n_1+p_2(1-p_2)/n_2}$

GIVEN, p_1=0.33, p_2=0.25, n_1=131, n_2=96

$\sigma _{\hat{p_1}-\hat{p_2}}=\sqrt{0.33(1-0.33)/131+0.25(1-0.25)/96}$

= $\sqrt{0.0017+0.0020}$

= $\sqrt{0.0037}$

=

ANSWER- THE STANDARD ERROR IS 0.0608

****IN CASE OF DOUBT, COMMENT BELOW. ALSO LIKE THE SOLUTION, IF POSSIBLE.