19. Based on the following mechanism for the ozone thermal decomposition into molecular oxygen ki 03(g)...
Ozone decomposes to molecular oxygen: 2 O3(g) ⇋ 3 O2(g). The following is a proposed mechanism for the reaction: Step 1: O3(g) ⇋ O2(g) + O(g) (fast) Step 2: O3(g) + O(g) ⇋ 2 O2(g) (slow) Provide a valid rate law for the overall ozone decomposition reaction based on this mechanism. 4. Ozone decomposes to molecular oxygen: 203(g) — 3 O2(g). The following is a proposed mechanism for the reaction: Step 1: 03(g) – O2(g) + O(g) (fast) Step 2:...
17. The following mechanism has been proposed for the thermal decomposition of ozone in the gas phase: 20 0 + 0₂ 0₂ + O₂ + 0 202 The rate expression for the production of oxygen is: A 3kı[O3] B) k2[O3][O] C) 2k1[O3] D) 2k1 [03]3/2 E) ki[O3]
4) Derive the rate law for the decomposition of ozone to molecular oxygen using the elementary steps provided below. The mechanism proposed for this process is assumed to be 03 4 0 + O2 0 +03 --202
12. The following mechanism is proposed for the decomposition of ozone (O3) to O2: 03 + M 02 + 0 + M 0+03 2 02 Apply the steady-state approximation to the concentration of atomic oxygen, and derive the rate law for the decomposition of ozone (M stands for a molecule that can exchange kinetic energy with particles undergoing the chemical reaction.) 12. The following mechanism is proposed for the decomposition of ozone (O3) to O2: 03 + M 02 +...
QUESTION 10 A proposed mechanism for the decomposition of ozone in the atmosphere is: Step 1: 03(g) + hvO(g) + O2(g) (fast) Step 2: O(g) + O2(g) +202() (slow) What is the molecularity of the rate-determining step? unimolecular bimolecular zeromolecular More information is needed. termolecular QUESTION 11 At a certain temperature the equilibrium equals 0.11 for the reaction: 2 ICI(g) =12(g) + Cl2(g). What is the equilibrium concentration of Cl2 if 2.78 mol of 12 and 2.78 mol of Cl2...
QUESTION 21 A proposed mechanism for the decomposition of ozone in the atmosphere is: Step 1: 03(g) + hv → O(g) + O2(g) Step 2: O(g) + O3(g) → 202(0) Does this reaction mechanism have an intermediate and/or catalyst? Only a catalyst Only an intermediate An intermediate and a catalyst More information is needed O Neither an intermediate nor a catalyst
Gaseous ozone undergoes decomposition according to the stochiometric equation: 203(g) →302 (g) Two alternative mechanisms have been proposed to account for this reaction. Mechanism 2 03 302 bimolecular, rate constant k Mechanism II 03 02 + fast equilibrium, equilibrium constant K1 0+ 03 — 202 slow, rate constant k2 A. Derive rate laws for the formation of O2 for each mechanism. B. Thermodynamic measurements give standard enthalpies of formation for each of the following species at 298 K: species AH°...
6. The decomposition of ozone in the upper atmosphere is catalyzed by NO. The overall reaction and rate law are: O:(g) + O(g) →202(g): rate = k[O][NOJ Write a possible mechanism that is consistent with rate law and identify an intermediate in the reaction. 7. A possible mechanism for the iodide ion catalyzed decomposition of hydrogen peroxide in aqueous solution is: H2O2(aq) + I'(aq) → H2O(l) + Of(aq) ---...-slow H2O2(aq) + Or(aq) → H2O(0) + O2(g) + I'(aq) -----fast What...
57.) The ozone, O3, of the stratosphere can be decomposed by reac- tion with nitrogen oxide (commonly called nitric oxide), NO, from high-flying jet aircraft. O3(g) + NO(g) → NO2(g) + O2(g) The rate expression is rate = k[O3][NO]. Which of the following mechanisms are consistent with the observed rate expression? (a) NO + 03 - NO3 + 0 (slow) NO3 +0 - NO2 + O2 (fast) O3 + NO → NO2 + O2 overall (b) NO + O3 ->...
1. When ozone absorbs ultraviolet light, it forms molecular oxygen. 203(g) + 302(g This reaction is believed to go by this simple mechanism: (1) 03(g) = 02(g) + 0(g) (2) 0(g) + 03 (g) → 202(g) Q3! containing only reactant and/or product (a) Using the steady-state approximation, determine an expression for concentrations (i.e. things that appear in the net reaction). (b) In the upper atmosphere, [03] is typically quite small compared to [02], which remains essentially constant since it is...