Need to know how to read each and determine the structure. Please list out step by...

Question

Question

Need to know how to read each and determine the structure. Please list out step by step. ***Especially number 6 please

Answer 1

Answer #1

Solution:

6) The given NMR spectrum confirms an ester:

C6H5 CH2-OCOCH2-CH3

A) IR explanation:

The presence of strong peak in IR at 1750 cm-1 confirms an ester.

B) NMR explanation:

> The presence of peak at 7.2 ppm due to 5H confirms the presence of monosubstituted benzene ring.

>> The presence of a singlet peak at 3.6 ppm due to 2H suggest that CH2 group is attached to benzene ring.

>> The triplet peak at 4.1 ppm due to 2H confirms that it is flanked between CH3 and C=O group

>> The triplet peak at 1.3 ppm due to 3H suggests terminal CH3 group.

Hence, molecular structure will be:

C6H5 CH2-O-COCH2CH3

Answer 2

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