Question

need to know how to read each(#16,17,18) and determine the structure. Please list out step by step.

Unknowns for 1H NMR Final Report 16) Chemical Formula: C.H.O. IR: strong peak 1720cm! 3H 17) Chemical Formulae: CzHs Singlet, 9H 4H, Doublet Triplet Triplet Doublet Triplet, 3H Quartet, 2H 5 PPM 18) Chemical Formula: CH120 IR: Strong broad peak at 3200 cm 5H Зн PPM

Answer 1

Ca te le DBE DBE = 4-84+1 = 1 so, only one double bond prescil and it is canberry I and that can be confinned for Strony IR peak 1720 cm (c=0 sto). Now if we compiled the WMR dota Chemical chiff menliphias integreton 1.1 ppm tripict : 34 2.45 une quarkt 24 138 ". A simp so, the structor will be - 34 singht 11 po short and 2:45ppm

110 2 E3 The the Now OBE = 12 - 19241 = 13-g'=4 so, one arometic moicly presal. benzene ring is dously substituted as integratia of benzem hydrogen is AH. singlel, gH refers to the group- Cl2 refer to Now, trißill at the gas quateli 24 2 the group - - CH3 so the shnetur ain sea 9,24 a singlel, gt, doubled É por tropht, 31te. It He tombit doublet tapet

18. Cg H2O I DBE - 9 -142+1 210-6= 4 So There must be a senzen ring. How, from IR there is a broad pen at 3200 cm-le and this is for -04 gooup. now, benene ring is singly substituted - as the total integrobit of hydrogen in Sil. 1H - triplet stands for the grap- 50, the the strucha win bent strela 04 (4.9 ppm) ohtla etz og ppn, 3Hit H144 ppm opening ix, 20,9 18 1H) ",24,9