Question

16) Chemical Formula: C_H2O2 IR: strong peak 1720cm-1 Зн Зн ' M

Please draw our structure and explain each step, thank u

Answer 1

Chemical C4H8 02 Formula degree's a unsatugation 2 C 2+ N - H-X 2. 24 2 +0-8 2- from degree s Ok unsaturution giyen contuin ging o Compound bond mmust OT One 2) IR 17 2 0 ml 1720 cm-1 from ir Compound given cerbonyl 9moup a functional aroup(aldeny de ketone data 720 cM^I) cont w n as 3) N M. R. triplet SH a) 2 CH2-CH3

2 4 E quartet 2H CH3 c) 3. 6 singket 3H CH3 hiqh chemicul shift vulue is cttaehed with drauing goup So qiven edeetron carrbon fnom I R und NMR frug ments we get foifowing CH3 CH3-CH3 compound given Structurc for I.R.-I720 cm-) I- 2 PP m CH CH3 2 4PPm 3. 6 Ppm

chemicl fomula - CgH120 degrees os un saturution 2c+ 2+N-H-X 2. 2*9+2-0-12 -O 2. 20-12 2. degoees ob unsuturution gYen bond's fom Compound One Col) oing cund contui n Pi borsds peak at 3200 cm 2) shong Strong pecak at 320 o cm -H is deto om i duta contwin Cumpound aven cas funcion a alcohol aYoup N. M. R 3H o. Ppm ±riplet a) CH3 CH2

b) 8 Ppm quintet 2 H -CH-cH2 - CH3 mdd 8.1 1H triplet Ppm ८म२ L L singlet Ppm o- H 4.7 Ppm 7. 3 - 7 4 chemicu Multip ret SH Ppm is high E provided by Sbift vulue signal arematic hydrogen's tnis is Frromn IR und NmR we 4) fo1lowing Get ragments. CM 3 CH2 O-H CH

structure o given ompound 4.7 OH - H CH CH2 CH3 OgPPm H T 8 PPm 7.3-7.4 PPm