Question

14) Chemical Formula: CH.0, IR: strong peak 1720cm, strong broad 3300cm 2H 2H 1н | 1ң PPM 15) Chemical Fomula: CsH02 IR: strong peak 1720cm, 1650cm (hard to see but, all peaks that integrate to 1H are doublet of doublets) Зн 1H 1H PPM

Answer 1

Chemical formula: C11H1403: Degree of unsaturation = ((2C+2)+N-H-X)/2 = (24+0-14-0)/2 = 5 4 sites account for benzene ring and one for carbonyl. Strong and broad peak at 3300:-OH stretching Strong peak 1720: carbonyl may be ketone or beta-oxy-ester. NMR: a: 1.5ppm: 3H, d: CH3-CH b: 3.2 ppm: 3H, S: CH3-0 C: 4.6ppm: 1H, q: CH3-CH-O d: 4.7ppm: 2H, s: Ar-CH2-O e: 4.9ppm: 1H. broad s: Ar-OH f: 6.8ppm: 2H, d: ortho to -OH g: 7.2ppm: 2H, d: meta to -OH These two signals suggest the para disubstituted benzene ring. doc. I CH2 CHP ga OH e methyl 2-[(4-hydroxyphenyl)methoxy]propanoate

15) C5H802 Degree of unsaturation = ((2C+2)+N-H-X)/2 = (12+0-8-0)/2 = 2 1 sites account for carbonyl and one for C=C, reffering to IR. Strong peak at 1720: C=O stretching 1650: C=C stretching NMR: a: 2.2ppm: 3H, S: CH3-CEC b: 2.3ppm: 3H, S: CH3-C=O C: 4.4ppm: 1H d: 4.6ppm:1H these last two peaks indicates terminal -C=CH2 group. Compound may be Isopropenyl acetate сн сна di 6H₃CT prop-1-en-2-yl acetate