Question

PPM 6) Chemical Formula: C2H,202 IR: strong peak 1750cm 2H 3 2 PPM 7) Chemical Formula: CH, N IR: weak peak at 3400cm 3H 8) Chemical Formula: CH120 IR: strong peak 1720cm,peak at 1650cm

Answer 1

* M. C10H12 o2 _ X degrees of Unsceturation = 2C+27N- 2 § 2410+2+0-12- 2 ; 22-12 = 10 -5 2. Given compound have five degrees of unseeturution lie-given compound have five double bond's or one phenyl ring and one double bond IR Salt 1 - a. 1750cm1 of ester. is due to a streck RT Co-Rz from I. R. giren I Ester functional compound have group

TH NMR a. 1.38 triplet 34 T Ib.8.6 - CH2 - CH3 singlet 24 -cha- T c. 4.2 quartet 24 -O CH-CH3 I d.9. 2f multiplet 5H fragment's from for. and o-Rz 8- CH2 - CH3 NMR -CH2- R tructure of the compound - 1750 cm -ot chat 4.2 1.38

ENTRO DATE * M. F. CSHIN degrees of Unsaturation = 2C+2+N-H-X 2 - -248 +2+1 -- - 1911-8 : - Giren Compound have four degrees of I Unsceturration i.e. It have four I double bonds as one phenyl ring - JR 0 due to N-4 3400 crit streel from J.R. go amine given compound have functional group. 1H NMR Q. 138 Lripet 31 - CH2 - CH3

IUNIE 1 b- 3.58 - quartet - 24 -N-CH2-CH3 c. 6.5-7.18 multiplet L 54 . .. 7.2 & singlet -7.28 J.R. and lyNmR.. I Ri - Ņ - R2 ; -N-CH2 CH3 ; FT Structure ols the compound 3.58 N - 42 € E H 3400ml 1:38 tot it S

STAO DATE DATE | L U BLOC *M.F - C8 H1204 degrees of Unsaturation : 24+2+N-H-X 2 1 248 +2+0-12-0 = = 18-12-06 S2 - - 3 Gixen Compound have a degrees of Unsaturation Tre. it have thre double bonet's a. 1920 cm i due to c=o street b.1650 cmt due to e-cStreet from I. R Given compound have two functional groups @ carbonyl - @ alkene (Q, ß unsaturated compound) IHNmR a. 1.2 8 triplet 64 CH₂-CH3 )

b.u.o8 quartet 44 -to- CH2- CHI) ____८. 6.58 21 ___ _CCC-11-65 from I.R following and IH NMR we have fragments -, 0-42-413), t c - 6, structure of the given compourel म. 6 120 26 - -0-12- - -CH-मार 12- 4.28 मना . 1 -CH - मर - 202 CH – CH3