Ans :
Amount of copper (II) fluoride = 0.205 umol = 0.000205 mmol
Volume of solution = 300 mL = 0.300 L
Concentration in mmol/L = mmol of solute / volume of solution in L
= 0.000205 mmol / 0.300 L
= 6.83 x 10-4 mmol/L
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