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A chemist prepares a solution of nickel(II) chloride (Nici, by measuring out 36. umol of nickel(II) chloride into a 450 ml vo
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Answer #1

moles of NiCl2 = 36. umol

volume = 450 ml = 0.450 L

concentration = moles / volume

                       = 36 / 0.450

concentration = 80. umol / L

concentration = 8.0 x 10^1 umol / L

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