moles of NiCl2 = 36. umol
volume = 450 ml = 0.450 L
concentration = moles / volume
= 36 / 0.450
concentration = 80. umol / L
concentration = 8.0 x 10^1 umol / L
A chemist prepares a solution of nickel(II) chloride (Nici, by measuring out 36. umol of nickel(II)...
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