Molar mass of HgI2,
MM = 1*MM(Hg) + 2*MM(I)
= 1*200.6 + 2*126.9
= 454.4 g/mol
mass(HgI2)= 2.2 mg
= 0.0022 g
use:
number of mol of HgI2,
n = mass of HgI2/molar mass of HgI2
=(2.2*10^-3 g)/(4.544*10^2 g/mol)
= 4.842*10^-6 mol
volume , V = 5*10^2 mL
= 0.5 L
use:
Molarity,
M = number of mol / volume in L
= 4.842*10^-6/0.5
= 9.683*10^-6 molL
Answer: 9.7*10^-6 mol/L
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