Question

A chemist prepares a solution of nickel(II) chloride (NiCl) by measuring out 54.7 jumol of nickel(II) chloride into a 150. ml. volumetric flask and filling the flask to the mark with water Calculate the concentration in mmol/L of the chemist's nickel(II) chloride solution. Round your answer to 3 significant digits.

Answer 1

Concentration = moles Volume (L) Here we have moles of Nicl2=54.7 umol = 54-7 umoL x 10 mol MAL = 54.7 x 100 mol of solution = 150 mi = 150 ml x 0.0012 Ime = 0.1504 volume .. concentration = 54.7 x 106 mol 0.150 L 3.65 x 104 mo Count = MOL IL figures In 3 significant Please Rate ...