Question

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Table 4. Group Data - Heat of Reaction of NaOH(aq) and HCl(aq) Solution. Groups .469 Molarity of NaOH 1. 2534 --055 0.16921 and HCl solution -2011 4803_0.7301.2971 mm AT (°C) 1.8 3.2 4. 4 11.3 3.3 q absorbed by 1,506.21 solution(J) Moles of HCI 0.2971 0.4593 0.2307 0.2411 0.4893 AH per mole of H20 59.441 (kJ/mol Moles of NaOH www .2534 50537692.2534 5055-

Answer 1

Entry 1.

q = n.c.$\Delta$T

Where 'n' is the moles of NaCl = 0.2534 mol

'c' is the specific heat of water = 75.312 J/mol.^oC

Here, the moles of NaCl = 0.2534 mol

i.e. q = 0.2534 mol * 75.312 J/mol.^oC * 1.8 ^oC = 34.351 J

And $\Delta$H = q/n = 34.351 J/0.2971 mol = 115.622 J/mol

Entry 2.

q = n.c.$\Delta$T

Where 'n' is the moles of NaCl = 0.4893 mol

'c' is the specific heat of water = 75.312 J/mol.^oC

Here, the moles of NaCl = 0.4893 mol

i.e. q = 0.4893 mol * 75.312 J/mol.^oC * 3.2 ^oC = 117.9205 J

And $\Delta$H = q/n = 117.9205 J/0.5055 mol = 233.275 J/mol