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A proton moves at 4.50 x 105 m/s in the horizontal direction


A proton moves at 4.50 x 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 9.60 x 103 N/C. Ignoring any gravitational effects, find (a) the time interval required for the proton to travel 5.00 cm horizontally, (b) its vertical displacement during the time interval in which it travels 5.00 cm horizontally, and (c) the horizontal and vertical components of its velocity after it has traveled 5.00 cm horizontally.


25a) Find the (x,y) components of F. 

b) Find the (x,y) components of a. 

c) Find the time needed to travel 5 cm horizontally. Remember cm → m 

d) Find the vertical distance the proton moves in this time. 

e) Using the (x,y) components of a (part b), determine the (x,y) components of vf after t = 5 seconds. 

f) What are the magnitude and direction of vf

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Answer #1

(a)

0.05 v4.50. 1051.11 x 10-7s

(b)

eE 1.6 10159.60 10 Cl 1.67.10-27 m/s-9.19 x 1011 m/s2 7m

y--at2ー . 9.19 . 1011 . (1.11 . 10-7)2 m 5.66 × 10-3 m

(c)

Vz 4.50 × 103 m/s

y -V2ay- V2.9.19 1011 5.66 10-3 m/s 1.02 x 10 m/s

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