Determine ΔrH° for the following reaction, 2 NH3(g) + 5/2 O2(g) → 2 NO(g) + 3 H2O(g) given the thermochemical equations below.
N2(g) + O2(g) → 2 NO(g) ΔrH° = +180.8 kJ/mol-rxn
N2(g) + 3 H2(g) → 2 NH3(g) ΔrH° = –91.8 kJ/mol-rxn2
2H2(g) + O2(g) → 2 H2O(g) ΔrH° = –483.6 kJ/mol-rxn
a. –1178.2 kJ/mol-rxn b. –452.8 kJ/mol-rxn c. –394.6 kJ/mol-rxn d. –211.0 kJ/mol-rxn e. +1178.2 kJ/mol-rxn
hence, option b is correct
Determine ΔrH° for the following reaction, 2 NH3(g) + 5/2 O2(g) → 2 NO(g) + 3...
Determine AH for the following reaction, 2NH3(g) + 5/20260) - 2NO(g) + 3H2019) given the thermochemical equations below. N2(g) + O2(0) - 2NO(g) N2(g) + 3H2(g) — 2NH3(0) 2H269) + O26) - 2H206) AH = +180.8 kJ AH = -91.8 kJ AH = -483.6 kJ -1178.2 kJ -452.8 kJ -394.6 kJ -211.0 kJ +1178.2 kJ
35. Calculate ΔrH° for the combustion of ammonia, 4 NH3(g) + 7 O2(g) → 4 NO2(g) + 6 H2O( ) using standard molar enthalpies of formation. molecule ΔfH° (kJ/mol-rxn) NH3(g) –45.9 NO2(g) +33.1 H2O( ) –285.8 a. +30.24 kJ/mol-rxn b. –206.9 kJ/mol-rxn c. –298.6 kJ/mol-rxn d. –1398.8 kJ/mol-rxn e. –1663.6 kJ/mol-rxn
Determine the standard enthalpy of formation of calcium carbonate from the thermochemical equations given below.Ca(OH)2(s) → CaO(s) + H2O()ΔrH° = 65.2 kJ/mol-rxnCa(OH)2(s) + CO2(g) → CaCO3(s) + H2O()ΔrH° = −113.8 kJ/mol-rxnC(s) + O2(g) → CO2(g)ΔrH° = −393.5 kJ/mol-rxn2 Ca(s) + O2(g) → 2 CaO(s)ΔrH° = −1270.2 kJ/mol-rxna.−1712.3 kJ/mol-rxnb.−1207.6 kJ/mol-rxnc.−980.6 kJ/mol-rxnd.−849.6 kJ/mol-rxne.−441.8 kJ/mol-rxn
Using the equations N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol C(s) + 2 H2 (g) → CH4 (g) AH° = -74.9 kJ/ mol H2 (g) + 2 C(s) + N2 (g) → 2 HCN (g) AH° = 270.3 kJ/mol Determine the enthalpy for the reaction CH4 (g) + NH3 (g) → HCN (g) + 3 H2 (g).
Use the ΔH°f values provided to determine ΔH°rxn for the following reaction CH4(g) + 3 Cl2(g) → CHCl3(l) + 3 HCl(g) ΔH°rxn = ? ΔH°f (kJ/mol): -75 -134 -92 A. +662 kJ B. +117 kJ C. -151 kJ D. -335 kJ The equation that corresponds to the enthalpy of formation for NH3(g) is A. N(g) + 3H(g) → NH3(g) B. N(g) + 3/2 H2(g) → NH3(g) C. 1/2 N2(g) + 3H(g) → NH3(g) D. 1/2 N2(g) + 3/2 H2(g) →...
Calculate the standard reaction enthalpy for the reaction N2H4(ℓ) + H2(g) → 2 NH3(g) given N2H4(ℓ) + O2(g) → N2(g) + 2H2O(g) ∆H ◦ = −543 kJ · mol−1 2 H2(g) + O2(g) → 2 H2O(g) ∆H◦ = −484 kJ · mol−1 N2(g) + 3 H2(g) → 2 NH3(g) ∆H◦ = −92.2 kJ · mol−1 1.) −243 kJ · mol−1 2.) −59 kJ · mol−1 3.) −935 kJ · mol−1 4.) −151 kJ · mol−1 5.) −1119 kJ · mol−1
5 Determine the standard enthalpy of formation of Fe2O3(s) given the thermochemical equations below. 2Fe(s) + 3/2 O2(g) → Fe2O3(s) AH(Fe2O3) = ? Fe(s) + 3 H2O() Fe(OH)3(s) + 3/2 H2(g) AH° = +160.9 kJ/mol-rxn H2(g) + 1/2O2(g) → H2O(1) A.H° = -285.8 kJ/mol-rxn Fe2O3(s) + 3 H2O(1) ► Fe(OH),(s) A,Hº +288.6 kJ/mol-rxn
1. Calculate AH for the reaction C2H4 (8) + H2() → C2H6), from the following data. C2H4 (g) + 3 02 (®) → 2 CO2 (s) + 2 H20 (1) C2H6 (g) + 7/2 02(g) → 2 CO2(g) + 3 H20 (1) H2 + 1/2O2() → H20 (1) AH = -1411. kJ/mole AH = -1560. kJ/mole AH = -285.8 kJ/mole 2. Calculate AH for the reaction 4 NH3(g) +502 (g) → 4 NO(g) + 6 H20 (g), from the following...
5. Given the following chemical equilibria, N2(g) + O2(g) = 2 NO(g) N2(g) + 3 H2(g) = 2 NH3(g) H2(g) + 1/2 O2(g) =H2O(g) Determine the method used to calculate the equilibrium constant for the reaction below. 4 NH3(g) + 5 O2(g) = 4 NO(g) + 6 H2O(g) K
15. Determine the standard enthalpy of formation of Fe2O3(s), 2Fe(s) + 1.5 02 (g) → Fe2O3(s) given the thermochemical equations below. (4 points) AFH° = +160.9 kJ/mol-rxn Fe(s) + 3 H20(8) - Fe(OH)3(s) + 3/2 H (9) H2(g) + 1/2 O2(g) → H2O(6) Fe2O3(s) + 3 H2O(0) - 2 Fe(OH)3(8) A-H° = -285.8 kJ/mol-rxn A,Hº = +288.6 kJ/mol-rxn