Question

3.08 Conservation of Momentum Lab 1. Use the given collisions and data to calculate the initial and final momentum for each collision. 2. Complete calculations totals in results table. Equations: p mv and2p Ep A. Elastic Collision between equal mass Momentum Final (kg"m/s) Momentum Initial (kg"m/s) Initial Velocity Final Velocity (m/s) Collision 1 Mass (kg) (m/s) Mass 1 2.0 +1.0 -1.0 Mass 2 2.0 -1.0 1.0 B. Elastic Collision between unequal mass: 2 Initial Velocity (m/s) Final Velocity (m/s) Momentum Initial (kg"m/s) Collision 2 Mass Momentum Final (kg m/s) (kg) Mass 1 0.50 1.0 -2.20 Mass 2 2.0 -1.0 0.20 C. Inelastic Collision between equal mass

Answer 1

Que :- A: Elastic collision between equal mass > for Mass 1 Momentum intial = 2 X +1.0 = +2 kg mis Momentum final = 2 X - 1.0 = - 2 kg mis as for Mass 2 Momentum initial = 2x - 1.0 =-2 kg m/s Momentumfinal = 2 x 1.0 = 2 kg .in/s B: Elastic Collision b/w unequal mass > four Mass 1 0.50 x 1 initial = Momentum Momentum 1 = 0.50 kg mle final = 0.50% - 2.20 = -1.1 kg mis - for Mass 2 Momentum initial = 2 x - 1.0 = -2.0ky mls final a 28-0.20 Momentum = -0.4 kg mis

C: inelastic Collision blu equal mass for Mass 1 Momentum initial = 2x1 - 2 kg mls Momentum final = 2x0 =0 for Mass 2 -2.0ke initial = 2X -1.0 = Momentum tined = 2x0=0 Momentum D: melastic collision b/w unequa for Masst Momentum initial = 0.50x1 = 0.5 kg m/s Momentum final = 0.50 % - 0.60 = -0.3 Kymys for Mass 2 2 - 2 kg mle x 1.0= initial = Momentum Momentum final = 2x -0.60=-1.2 kg mis Results:- lis momentu is momentum conserved Teollicia Total Momentum Total Momentum O final | Total Monestun initial = 0 -2 +2 = 0 +2 -2 Yes Collision 1 -1.1 -0.4 = -1.5 Yes I collision 2 = -115 0.5 - 2 I lision 1 2 - 2 - 0 0 + 0 = 0 Yes collision 4 0.5-2 -1.5 *0.3 - 1.2=1.5 Yes